How Does Friction Affect Cars on Circular Tracks Compared to Straight Roads?

AI Thread Summary
Friction plays a crucial role in a car's movement on circular tracks compared to straight roads. In circular motion, friction is static because the tires maintain rolling contact with the surface, preventing skidding. This static friction acts in the direction of the centripetal force, allowing the car to navigate curves without losing traction. In contrast, on straight roads, friction is typically absent when the car moves at a constant speed, as there is no relative motion between the tires and the ground. Understanding these differences is essential for analyzing vehicle dynamics in various driving scenarios.
ajaysabarish
Messages
58
Reaction score
0
Member warned about proper use of the template and showing an attempt at solution.
please explain the phenomenon of friction acting on a car moving in a circular track.also explain how is this friction static and how is this friction different from the friction acting on a car moving on a straight road.
 
Physics news on Phys.org
ajaysabarish said:
please explain the phenomenon of friction acting on a car moving in a circular track.also explain how is this friction static and how is this friction different from the friction acting on a car moving on a straight road.
As per forum rules, you must show some attempt at a solution. List any standard equations or principles you believe may be relevant.
 
haruspex said:
As per forum rules, you must show some attempt at a solution. List any standard equations or principles you believe may be relevant.
thank you very much for replying,sir.this isn't any homework question but a doubt, i got while solving problems.when i was trying to attempt problems involving friction in a circular track,i found it very much different from friction in a straight track.for example the direction of friction was no more opposite to direction of relative motion,and the friction is considered to be static while the car is moving.so please explain the entire phenomenon of friction acting on a circular track for car,particle,etc.
 
ajaysabarish said:
the friction is considered to be static while the car is moving

The car isn't skidding so the tyres aren't sliding over the surface.
 
ajaysabarish said:
the direction of friction was no more opposite to direction of relative motion,
Friction opposes relative motion of the surfaces in contact. That means it acts not only against any actual motion but also against any tendency to motion.
For a rolling wheel at constant speed in a straight line on a level, stationary surface, there is no tendency to relative motion. The part of the tyre in contact with the ground would be stationary relative the ground even without friction (so there isn't any). Only when the wheel speeds up or slows down, or changes direction, or starts to go up or down a slope, will there be any risk of sliding.
ajaysabarish said:
the friction is considered to be static while the car is moving
It's not to with whether the car is moving. What matters is whether the tyres are in rolling contact.
See if this helps: https://www.physicsforums.com/insights/frequently-made-errors-mechanics-friction/
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top