How Does Friction Affect the Deceleration and Distance Traveled by a Motorboat?

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The discussion focuses on the effects of friction on a motorboat's deceleration and distance traveled after the engine is turned off. The friction force is defined as F = -αν - βv², leading to a differential equation for the boat's velocity. Participants suggest solving the equation using integration techniques, specifically with boundaries set from the initial speed v₀ to one-third of that speed. There is a correction noted regarding the sign and factors in the equation, emphasizing the importance of accurate variable representation. The conversation highlights the need for clarity in mathematical expressions to effectively analyze the problem.
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Homework Statement


When engine was turned off,boat with mass m was moving with speed v_0.
The force of friction F=-\alpha\nu-\betav^2.
How long it would take to drop speed of boat 3 times?
Find the distance which the boat will travel in this time?


Homework Equations





The Attempt at a Solution


I think i should try to solve differental equation in form of
m\dot{v_0}=-\alpha\nu-\betav^2

But I really don't know what to do next,could someone,please help me with some steps or tips?


 
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Ok,now I am pretty sure that i have to solve DE :
\int(\frac{dv}{ \alpha v+\beta v^2})=\int dt

And integration bondaries from v=v_0 to v_0/3 ?
And for other intergral offcourse its fromt=0 to t_0

Either way, how can I find the distance?

Please help .
 
Hint: Use
$$a = \frac{dv}{dt} = \frac{dv}{dx}\frac{dx}{dt} = v\frac{dv}{dx}.$$ This is just the chain rule.
 
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prehisto said:
Ok,now I am pretty sure that i have to solve DE :
\int(\frac{dv}{ \alpha v+\beta v^2})=\int dt

And integration bondaries from v=v_0 to v_0/3 ?
And for other integral of course its from t=0 to t_0
You dropped a minus sign (as well as a factor m). You could fix the sign by changing the v limits to being from v0/3 to v0.
I note that in the OP you gave the force as being ##-\alpha \nu -\beta v^2##. I assume you meant ##-\alpha v -\beta v^2##
 
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