How Does Gravity Affect the Trajectory of an Artillery Shell?

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Gravity significantly influences the trajectory of an artillery shell after it exits the barrel, primarily by pulling it downward against the initial propulsion force. The shell follows a parabolic flight path, which is affected by factors such as launch angle and wind resistance. The initial propulsion force decreases over time due to gravity, eventually leading to the shell's descent. To estimate the trajectory, one can apply projectile motion equations that incorporate these variables. Understanding these principles is crucial for accurately predicting the shell's behavior in flight.
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Hey, I'm doing a math project on projectiles (I think) and I was wondering how to determine how let's say... an artillery shell would act after it leaves the barrel. I was wondering when the forces of gravity would overcome the initial propulsion force and begin to bring the shell down. I know that the angle of the shot, wind etc. would effect this, but just like a rough estimate.

I'm guessing the flight path would look something like a stretched out parabola, but I'm unsure about how to determine those factors.
 
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See for more information on projectile motion:
http://id.mind.net/~zona/mstm/physics/mechanics/curvedMotion/projectileMotion/generalSolution/generalSolution.html
 
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