How Does Heat Affect the Bullet-Wood Problem?

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How is the bullet-wood problem different in setup if:
a)the bullet stops in the wood
b)if the bullet goes through the wood?

Is it that (a) would be an inelastic and (b) would use conservation of momentum?

Other question is how can energy loss by heat be calculated by this type of problem?
 
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infraray said:
How is the bullet-wood problem different in setup if:
a)the bullet stops in the wood
b)if the bullet goes through the wood?

Is it that (a) would be an inelastic and (b) would use conservation of momentum?

Other question is how can energy loss by heat be calculated by this type of problem?
Both are inelastic and both conserve momentum. Heat would be calculated by finding the mechanical energy lost in the process.
 
Yes, in both cases kinetic energy is not conserved. When calculating the heat energy which is equivalent to loss in KE, we have to assume that no energy is converted to producing sound.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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