How Does Magnet Size Affect Lenz's Law in Falling Magnet Experiments?

AI Thread Summary
The size of the magnet significantly impacts the effects observed in falling magnet experiments related to Lenz's Law. A magnet that is smaller than the tube diameter would require a much stronger magnetic field to produce noticeable effects due to reduced proximity to the metal. The interaction between the falling magnet's time-varying magnetic field and the induced current in the tube generates a magnetic field that opposes the magnet's fall, as described by Lenz's Law. Larger magnets produce stronger magnetic fields and greater induced currents, enhancing the observable effects. Overall, the size of the magnet is crucial for demonstrating the principles of Lenz's Law effectively.
gildomar
Messages
98
Reaction score
2
In all demonstrations of Lenz's Law that I've seen about the falling magnet, the diameter of the magnet is roughly the same size as that of the tube. Would there be any difference if the magnet was significantly smaller?
 
Physics news on Phys.org
I think the proximity of the magnet to the metal helps the cutting of the magnetic flux. If you think of the extreme, a pea sized magnetic falling through a tube with a diameter of 1 meter would need to be VERY strong to see any effect. I am by far no expert though.
 
  • Like
Likes gildomar
The tube produces a magnetic field in response to the change in magnetic field from the falling magnet. To produce a large force, you want those magnetic field sources near each other, and that argues for a large magnet. Additionally, all other things being equal, you get a stronger field from a bigger magnet.
 
  • Like
Likes gildomar
More precisely the time-varying magnetic field of the falling magnet leads to an electromotive force, according to Faraday's Law,
$$\frac{1}{c} \dot{\vec{B}}+\vec{\nabla} \times \vec{E}=0.$$
This leads to a current in the tube (or coil). This current leads to a magnetic field, according to the Ampere-Maxwell Law,
$$-\frac{1}{c} \dot{\vec{E}}+\vec{\nabla} \times \vec{B}' = \frac{1}{c} \vec{j}.$$
The so "induced" magnetic field acts back on the magnetic moment of falling magnet in such a way to hinder it falling (Lenz's Law).
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top