How Does Mass Affect Velocity in a Two-Ball Pendulum Collision?

AI Thread Summary
In the discussion about the two-ball pendulum collision, the focus is on calculating the velocity of a lighter ball (32 g) before it impacts a heavier ball (80 g) after being released from a 60° angle. The formula used for the calculation is V = √[2gl(1 - cos(θ))], where g is the acceleration due to gravity and l is the length of the pendulum. The initial calculations provided by a user led to an incorrect result, prompting requests for clarification. Another participant pointed out that the answer is embedded within the question itself, suggesting a revision of the formula. The correct approach emphasizes the importance of accurately applying the physics principles involved in pendulum motion.
chazgurl4life
Messages
52
Reaction score
0
Two balls, of masses mA = 32 g and mB = 80 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60° angle with the vertical and released.a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)


a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)

i have been using the formula V=M+m
---- X (2gl(1-cos of the angle)^1/2
m


so when i put it all together i get :

V= .08kg+.032Kg
---------- X (2*9.8*.3m*1-cos60 degrees)^1/2
.032 kg

V=3.5 X(2.94)^1/2
V=6 m/s

but apparently this answer is wrong ..can anyone help ??
 
Physics news on Phys.org
You solved too far. The answer is in your question.(modified slightly with brackets).
chazgurl4life said:
a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)

[2gl(1-cos of the angle)]^1/2
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top