How Does Momentum Conservation Determine Velocities in Collisions?

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Momentum conservation dictates that the total momentum before a collision equals the total momentum after the collision. In this scenario, a 3.5 kg lawn bowling ball traveling at 12.3 m/s collides with a stationary 0.6 kg pin, which then moves at 34.4 m/s. The equation 3.5*12.3 = 3.5v + 0.6*34.4 is used to find the ball's new velocity after the collision. By equating the momenta before and after the event, the calculation reveals the ball's new velocity. This principle illustrates how momentum conservation governs the velocities of colliding objects.
StotleD
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Let's say you throw a 3.5 kg lawn bowling ball forward (that is in the positive direction) at 12.3 m/s and it hits a 0.6 kg "pin" that is at rest. If the pin flies forward at 34.4 m/s, what is the ball's new velocity?
 
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StotleD said:
Let's say you throw a 3.5 kg lawn bowling ball forward (that is in the positive direction) at 12.3 m/s and it hits a 0.6 kg "pin" that is at rest. If the pin flies forward at 34.4 m/s, what is the ball's new velocity?

Just solve the following equation:

3.5*12.3 = 3.5v + 0.6*34.4
 
The total momentum before and after remains equal in absence of external forces , Equate the momenta before and after the event.

Initially : Ball's momentum with 'v' in positive sirection

Finally: PIN's momentum in positive direction+ Ball's mometum in negative x direction

Equate them.

BJ
 

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