How Does Object Distance Affect Image Position in Refraction Problems?

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The discussion revolves around determining the image position in a refraction problem involving a glass rod with a convex hemispherical surface. The object is placed at an infinitely far distance, meaning the light rays are parallel as they approach the glass. Participants clarify that the distance of the object being at infinity simplifies the analysis of light behavior upon striking the surface. They suggest using standard equations for spherical surfaces or deriving results from Snell's Law to find the image position. Understanding the behavior of horizontal rays after striking the hemispherical surface is crucial for solving the problem.
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another refraction question??

The left end of a long glass rod 6.00 cm in diameter has a convex hemispherical surface 3.00 cm in radius. The refractive index of the glass is 1.60.

Determine the position of the image if an object is placed in air on the axis of the rod at the infinitely far distance to the left of the vertex of the curved end.



what does that mean? so is the distance of the object at infinity? I drew a picture for this problem, however the wording is confusing Maybe you might be able to tell me what they mean about the distance of the actual object?? Thankss!
 
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sghaussi said:
what does that mean? so is the distance of the object at infinity?

Putting the object at infinity just makes the light rays parallel and horizontal upon reaching the glass rod. Can you figure out what happens to a horizontal ray after striking the hemispherical glass surface at various positions?

Which equations are available to you? There are standard equations for spherical lenses/surfaces, but you can also derive the result from Snell's Law.
 
Ok, I just saw your other post. You can use the same equation I gave you there to do this problem.
 
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