How Does Pulse Duration Affect Frequency Spread in a Gaussian-Enveloped Laser?

leroyjenkens
Messages
615
Reaction score
49

Homework Statement



A laser with λ = 1 μm is pulsed (turned on and then back off) with a duration of 100
fs. What is the resulting frequency spread Δf in output of the pulsed laser? Assume that
the pulse has a Gaussian envelope.

Homework Equations



Not really sure, but possibly
ψ(x,0) = Ae-Δk2x2cos(k0x)

f=\frac{c}{λ}

The Attempt at a Solution


I'm not sure what I'm being asked to find here. The change in frequency? Is there an initial frequency and then there's a change in the frequency after the pulse is released from the laser? Does the frequency change from what it was at the beginning of the pulse, to when the pulse ends?

I converted the units to find that during the duration of the laser being on, 30 wavelengths of light was released. Not sure if that matters. Pretty lost here.

Thanks.
 
Physics news on Phys.org
The original wavelength is the central line; the really short pulses (100 fs = ultrafast laser).

They are asking for the bandwidth required to support a 100 fs pulse. Since your pulse is given as Gaussian you should know something about the time-bandwidth product, which is a Fourier analysis theorem.

See http://chirality.swarthmore.edu/PHYS81/UltrafastPulses.pdf
 
Last edited by a moderator:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top