How Does Static Friction Affect Bicycle Acceleration?

AI Thread Summary
Static friction plays a crucial role in a bicycle's acceleration by providing the necessary horizontal force without causing the wheels to slip. The free body diagram for the bike includes downward weight from each wheel, upward normal forces, rolling friction on the front wheel, and static friction on the rear wheel. The force of static friction is influenced by the weight distribution, which shifts towards the rear wheel during acceleration, potentially changing from a 50/50 to a 60/40 ratio. When calculating the frictional force, it is essential to consider the weight on the rear wheel multiplied by the coefficient of friction. The total mass used in the F=ma equation should include both the rider and the bicycle for accurate acceleration calculations.
7.11brown
Messages
2
Reaction score
0

Homework Statement


Consider a biker riding on level ground as shown. She wants to have the maximum forward acceleration possible, which means experiencing the maximum horizontal force without her wheels slipping. Draw the free body diagram for the bike accelerating forward.


Homework Equations


F=ma
kinetic friction is zero


The Attempt at a Solution


there would be weight going down from each wheel (dependent on the balance of the rider), a Normal Force from each going up, rolling friction on the front wheel and static friction in the direction of acceleration on the rear wheel

Is that correct? Would the force of static friction only be dependent on the weight the rider puts on the rear wheel?
 
Physics news on Phys.org
The force of friction would also depend on how much the center of gravity shifts to the rear when she accelerates. For example suppose when not accelerating the bike/rider has a 50/50weight distribution. But when it accelerates, the CG shifts rearward which increases the weight on the rear wheel. It could then be 60/40 or some other ratio.
 
Just to make sure, my description of the free body diagram looked correct? If so, when calculating the frictional force, it would just be equal to the y component of weight on the rear wheel (assuming rolling friction is negligible.)? We are assuming a 50/50 weight distribution.

When using F=ma to find the acceleration of the bike and rider, would that mass be equal to the total mass since that is what is accelerating?

Thanks
 
"there would be weight going down from each wheel (dependent on the balance of the rider), a Normal Force from each going up, rolling friction on the front wheel and static friction in the direction of acceleration on the rear wheel"

Since you mention the weight going down and the normal force from pavement going up on each wheel, shouldn't you also mention the propulsion force that equals the friction force due to weight on rear wheel times coefficient of friction? Also in this vein, should you mention both forward and backward forces on front wheel. Don't forget, the front wheel is accelerating angularly so there is a torque term (due to angular acceleration) that equals the friction term.

"When using F=ma to find the acceleration of the bike and rider, would that mass be equal to the total mass since that is what is accelerating?"

Absolutely. It's the rider's mass plus the mass of bicycle.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top