How Does the Angle of Pulling Affect Kinetic Friction on a Box?

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The discussion revolves around a physics problem involving a box being pulled across a horizontal surface with a force of 110N. The box weighs 150N, and the kinetic frictional force is noted to be twice as large when the pulling force is horizontal compared to when it is applied at an angle. A participant attempts to solve for the angle but realizes their initial equation setup is incorrect. Clarification is provided that when the force acts at an angle, the kinetic friction is half that of the horizontal pull. The conversation emphasizes understanding the relationship between the angle of pull and kinetic friction in this context.
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Homework Statement



A box has a weight of 150N and is being pulled across a horizontal floor by a force that has a magnitude of 110N. The pulling force can point horizontally, or it can point above the horizontal at an angle (?). When the pulling force points horizontally, the kinetic frictional force acting on the box is twice as large as when the pulling force points at the angle (?).

Homework Equations



Find (?)

The Attempt at a Solution



I set up my equation to be 2(150)=150 - 110sin43.
...which is not right.
any help would be greatly appreciated :)
 
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pope 17, welcome to Physics Forums!

How did you determine that the angle is 43 degrees, if your equation was set up incorrectly?

Re-wording the problem, note that when the pulling force acts at an angle , the kinetic friction force is 1/2 the kinetic friction force when the pulling force acts horizontally.
 

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