How Does the Energy Density of a Lead-Acid Battery Compare to Gasoline?

AI Thread Summary
A fully charged 15.0 kg lead-acid battery delivers 1450 W for one hour, equating to a total energy output of 5.22 MJ. When comparing this to gasoline, which has a heat of combustion of approximately 44 MJ/kg, the energy density of the lead-acid battery is significantly lower. The calculated energy density of the battery is about 348 kJ/kg. This stark difference highlights the limitations of lead-acid batteries in terms of energy storage compared to gasoline. Understanding these energy densities is crucial for applications in energy storage and transportation.
aaronb
Messages
22
Reaction score
0

Homework Statement


A fully charged 15.0 kg lead-acid battery can deliver power 1450 W for 1.0 hr. (For comparison, the "heat of combustion" of gasoline is about 44 MJ/kg.)

Battery _____ MJ/kg

Homework Equations


Unit conversion problem
1W = 1 J/s

The Attempt at a Solution


(1450 J/s / 15kg) = 96.7/10^6 = 9.6 *10^-5
 
Physics news on Phys.org
Please don't multiple post
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top