How does the formula sheet help solve the problem?

  • Thread starter Thread starter Matt1234
  • Start date Start date
  • Tags Tags
    deriving Formula
AI Thread Summary
The discussion focuses on understanding how a formula sheet aids in solving physics problems related to motion. The user is confused about the relationship between the area under a graph and the formulas for displacement and acceleration. It is clarified that the area of a triangle can be represented using the acceleration, which is the slope of the velocity-time graph. The user is guided to substitute values from the formula sheet to derive the displacement equation. This highlights the importance of using the formula sheet to connect different concepts in physics.
Matt1234
Messages
141
Reaction score
0

Homework Statement



See the attachment please.


The Attempt at a Solution



I know the v1 x delta (t) is for the rectangle,
I don't see how the second part works? I don't understand why the t^2 and how a replaces the area formula i have written.


Thanks for your help, its my first day of class today, and its been a while since i was last in a physics / math class.

EDIT: I added a formula sheet we were given, sorry i just don't see the relationship right now..
 

Attachments

  • Scan.jpg
    Scan.jpg
    11.9 KB · Views: 425
  • Scan1.jpg
    Scan1.jpg
    8 KB · Views: 428
Last edited:
Physics news on Phys.org
You can replace \Delta v = v_2 - v_1 by the acceleration a. In the picture, the acceleration is the slope of the line, algebraically it is given by
a = \frac{\Delta v}{\Delta t}.

So just write down the area of the triangle and do the substitution.
 
from the second equation on the formula sheet,
a=\Deltav/\Deltat
a=(vf-vi)/t

from the graph, d=vit+\frac{1}{2}(vf-vi)*t
therefore, d=vit+\frac{1}{2}at2
(since vf-vi=at)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top