How Does the Function Transform from \( x = e^{2t} \) to \( x = e^{-2t} \)?

[nameVoid]

x=e^(2t)

y=t+1

t= ( lnx ) / 2

y= ( lnx ) / 2 + 1

or

blah

 

[Mark44]

x=e^(2t)

y=t+1

t= ( lnx ) / 2

y= ( lnx ) / 2 + 1

or

y= +- ( ( lnx ) / 2 + 1 ) ?

Why did you add +- ?

 

[nameVoid]

what i meant was for t<0 how to represent the graph in terms of y and x

 

[nameVoid]

x=e^(-2t)
y=t+1

-2t=lnx
y=1-lnx/2
i suppose

 

[HallsofIvy]

x=e^(-2t)
y=t+1

Is this the same question? How did "x= e^{2t}" become x= e^{-2t}?

-2t=lnx
y=1-lnx/2
i suppose

Assuming you really did mean x= e^{-2t}, yes, that is correct.