How Does the Symmetry of Sine Influence the Distribution of Y = sin(X)?

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Suppose X ~ U[ 0, pi ]

What is the distribution of Y=sinX.

I have a solution in my notes however I don,t understand the following the second transition:
<br /> F_Y(y) = P(Y \leq y) = P(X \leq \arcsin(y)) + P(X \geq \pi - \arcsin(y)) = ...<br />

Where the P(X \geq \pi - \arcsin(y)) comes from?
 
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The sine function is not monotonic.

Y is smaller than y if either of the arguments on the RHS are fulfilled.
 
Since the sin function is symmetric about ∏/2, there are two possible ranges you need to consider for the same values(imagine drawing a straight horizontal line at any 'y' on the sin curve, there are two symmetric value intervals below it), from [0, arcsin(y)] and [∏ - arcsin(y), ∏] which can be reflected in the solution.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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