How does the Tamper in a nuclear bomb survive?

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The discussion focuses on the role of the tamper in nuclear bomb design, specifically its ability to facilitate the compression of fissile material to achieve critical mass. It is clarified that while the tamper is mechanically destroyed during the explosion, its inward movement is crucial for the process. The momentum generated by the tamper contributes to the efficiency of the chain reaction, despite the material's destruction. The conversation emphasizes that the tamper's function is not compromised by its physical destruction, as its movement is what matters. Overall, the mechanics of the tamper are essential for triggering the nuclear reaction effectively.
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I can't really explain my query fully in the space of a title but after hearing an explanation about how nuclear bombs work there is one thing I don't understand - the fissile material is in the centre, around that is the neutron deflector and around that the conventional explosives (this is probably a simplification). The shock waves from the conventional explosives must squeeze the fissile material to critical mass to trigger the chain reaction, but the shock wave must travel through the tamper first. Why is the tamper not destroyed? If the blast is powerful enough to cause critical mass surely any material used for the tamper would not survive?
 
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It all gets compressed. The time involved is very short.
 
The tamper gets destroyed mechanically - it doesn't matter, as long as it moves inwards it serves its purpose.
 
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mfb said:
The tamper gets destroyed mechanically - it doesn't matter, as long as it moves inwards it serves its purpose.

So it gets destroyed but still can do its job - thank you.
 
gvlr96 said:
So it gets destroyed but still can do its job - thank you.
The momentum of the tamper does the job. A structure can be destroyed; momentum can not be.
 
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