How Does the Tension in a Cord Between Two Masses Compare to an Applied Force?

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SUMMARY

The discussion focuses on the dynamics of two masses, "P" and "Q," connected by a light cord on a frictionless surface, with an applied horizontal force "F" on mass "Q." The conclusion is that the tension in the cord (T) exerted on mass "P" is less than the applied force "F" but not zero, confirming that the correct answer is "C." The reasoning involves analyzing the forces acting on both masses and applying Newton's second law (F = ma).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of force diagrams (Free Body Diagrams)
  • Concept of tension in connecting cords
  • Frictionless surface dynamics
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  • Study the application of Newton's second law in multi-body systems
  • Learn how to draw and interpret Free Body Diagrams (FBDs)
  • Explore the concept of tension in different mechanical systems
  • Investigate the effects of friction on tension and force dynamics
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Homework Statement



Two bodies "P" and "Q" are on a frictionless horizontal surface are connected by a light cord. The mass of "P" is greater than that of "Q." A horizontal force "F" is applied to "Q" as shown below, acceleration the bodies to the right. The magnitude of the force "F" exerted by the connecting cord on body "P" will be:

A. Greater than F
B. Zero
C. Less than F but not zero
D. Equal to F

Homework Equations



F = ma?
I drew a picture.

The Attempt at a Solution



I thought the answer was "A" because the force has to account for mass "P" AND mass "Q."
 

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Let The Tension in the connecting cord of P and Q be T. Now draw the FBDs. I think the answer should be C.
 
vivekrai said:
Let The Tension in the connecting cord of P and Q be T. Now draw the FBDs. I think the answer should be C.

You are right; the answer IS C. I was thinking of the force in front of "Q."
 

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