an observation or two..
After switch closure...
The capacitor
charges while the relay contact is OPEN , through the lights
because
on one side it sees battery through 47 ohms, on other side it sees ground through the lights.
The capacitor
discharges while the relay contact is closed. because It sees battery voltage on both sides.
The current required to open the contact is substantially greater than the current required to hold it open, because when it's open the air gap is smaller.
Starting at the instant switch gets closed,,,,,
Lamp current through right hand winding makes flux that opens the contact. But not immediately.
By Lenz's law, current is induced in the left hand winding to oppose
increasing flux. There's
@Averagesupernova 's opposing fields ..
That places some charge on the capacitor.
Flux rises because of lamp current
until the contact opens. .
Now lamp current goes away so flux tries to decrease
and current in left coil reverses to oppose
decreasing flux.
Current through the capacitor and left hand coil , now reversed, holds the contact open for a few time constants. 4700 microfarads X 47 ohms is 0.22 second..
When capacitor charging current decreases to minimum relay holding current the contact closes again.
So it would be very interesting to observe voltage from the junction of left hand coil and capacitor to "gnd" . Does it ever get above 6 volts ?
If i understand this thing at all
Voltage across the 47 ohm resistor will alternate its polarity every time the relay changes state.
Check my logic please ?
..............................
btw i observed my blinkers today. On my 2002 Ford Escort the first flash is perceptibly longer. But it's driven by a relay with a half dozen wires so i don't know whether timing is set by a computer or something analog like your clever flasher. .
Changing the taillights to LED made it flash way too fast so something is measuring current.
old jim