How Does Torque Relate to Magnetic Dipole Moment in Physics?

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Homework Help Overview

The discussion revolves around the relationship between torque and magnetic dipole moment, specifically starting from the Lorentz force law and exploring how to derive the expression for torque on a steady current distribution in a uniform magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the derivation of torque from the Lorentz force law and are questioning the steps involved, particularly after taking the derivative of the torque equation. There are inquiries about the definitions of terms such as magnetic dipole moment and the variables involved.

Discussion Status

The discussion is ongoing, with participants seeking clarification on specific terms and steps in the derivation process. Some guidance has been offered regarding the definition of magnetic dipole moment, but there is still a lack of consensus on the next steps in the derivation.

Contextual Notes

Participants are referencing a specific textbook (Griffiths 4ed) and are working under the constraints of deriving a general expression applicable to various current distributions, not limited to simple geometries.

ghoul
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Homework Statement


Starting from the Lorentz force law, in the form of Fmag = ∫ I (d× B), show that the torque on any steady current distribution (not just a square loop) in a uniform field B is m × B.

Homework Equations


I looked at the solution I found in this thread here, but I don't understand the step after you take the derivative of both sides of the torque equation. Why would you use that method in the next step, and how? Where did it come from?

I have Griffiths 4ed.

The Attempt at a Solution


This is all I know how to do.
ubsqgCZ.jpg
 
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ghoul said:

Homework Statement


Starting from the Lorentz force law, in the form of Fmag = ∫ I (d× B), show that the torque on any steady current distribution (not just a square loop) in a uniform field B is m × B.

Homework Equations


I looked at the solution I found in this thread here, but I don't understand the step after you take the derivative of both sides of the torque equation. Why would you use that method in the next step, and how? Where did it come from?

I have Griffiths 4ed.

The Attempt at a Solution


This is all I know how to do.
ubsqgCZ.jpg

Hi mister ghoul! :oldsmile:

What is ##\mathbf m##?
 
Last edited:
I like Serena said:
i mister ghoul! :oldsmile:

What is ##\mathbf m##?
Hi,
I believe that m is magnetic dipole moment. m = Ia
 
ghoul said:
Hi,
I believe that m is magnetic dipole moment. m = Ia

Okay... so what is ##\mathbf a##?
We'll need some expression to substitute, which will hopefully lead to the requested result.
 

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