How Does Varying Charge Affect Initial Acceleration of Point Charges?

pimster987
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Q1. If two point charges have equal mass and and charg are released on a frictionless table, each has an initial acceleration (Ao). if instead you keep one fixed and release the other one, what will be its initial acceleration?Ao,2Ao or Ao/2?


Q2. A point charge of mass (m) and charge (q) and another point charge of mass (m) but charge (2q) are released on a frictionless table. If the charge (q) has an initial acceleration (Ao), what will be the acceleration of (2q)?Ao, 2Ao, 4Ao,Ao/2, or Ao/4?
 
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Q1 Since both charges are the same they will repel one another. So I was comparing this problem to a ping pong ball problem I had in Physics I, when the force of the wall equals the force of the ball thrown. Wouldn't the acceleration just be Ao?

Q2 Since F=ma the mass is proportional to the acceleration therefore the acceleration should be 2Ao.
 
1. I believe you're correct

2. Look at that equation carefully: the mass is not proportional to the acceleration.
 
They are inversely proportional so the acceleration should be Ao/2?
 
You're right that in F=ma, the mass and acceleration are inversely proportional. But what are the masses of the two particles?
 
i think you are wrong guys, because it's an electric force not an applied force.
so the acceleration = Ao . o:)
 
i think you are wrong guys, because it's an electric force not an applied force.
so the acceleration = Ao .
[they have the same acceleration ]
 
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