How Does Wind Affect the Maximum Roundtrip Distance of a Jetliner?

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The discussion focuses on calculating the maximum roundtrip distance a jetliner can travel while accounting for wind effects. The jetliner can fly for 6 hours and has a speed of 240 m/s without wind, but faces a 57.8 m/s headwind on the outbound leg and a tailwind on the return. The velocities calculated for each leg of the trip are 182.2 m/s westward and 297.8 m/s eastward. The challenge lies in determining how to divide the total flight time between the two legs to ensure the distances are equal. The solution involves setting up two equations based on the relationship between speed, time, and distance.
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A jetliner can fly 6.00 hours on a full load of fuel. Without any wind it flies at a speed of 240 m/s. The plane is to make a roundtrip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 57.8-m/s wind from the jet stream, which blows from west to east. What is the maximum distance that the plane can travel due west and just be able to return home?

I've already calculated that the velocity of the plane on the way there is 182.2 m/s and on the way back is 297.8 m/s. I'm just not sure how to determine how to divide the distance. I tried using 3 hours there, 3 hours back, but the distances were uneven. Help! Is there a formula (or formulas) that I can use?
 
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pippintook said:
A jetliner can fly 6.00 hours on a full load of fuel. Without any wind it flies at a speed of 240 m/s. The plane is to make a roundtrip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a 57.8-m/s wind from the jet stream, which blows from west to east. What is the maximum distance that the plane can travel due west and just be able to return home?

I've already calculated that the velocity of the plane on the way there is 182.2 m/s and on the way back is 297.8 m/s. I'm just not sure how to determine how to divide the distance. I tried using 3 hours there, 3 hours back, but the distances were uneven. Help! Is there a formula (or formulas) that I can use?

You have 297.8 * x hours = 182.2 * y hours and you know that x + y = 6.

2 Equations, 2 unknowns
 
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