How Does Wind Speed Affect Roof Pressure in a Storm?

AI Thread Summary
Wind speed significantly impacts roof pressure during storms, with higher speeds leading to greater pressure differences. In this scenario, a roof area of 92.8 m² experiences wind at 106.8 km/hr, resulting in a calculated pressure difference using the formula involving air density. The air density is assumed to be 1.25 kg/m³, and the pressure difference is derived from Bernoulli's principle. The discussion raises questions about the correct approach to calculating time and whether the initial method is appropriate. Understanding these principles is crucial for assessing structural integrity during severe weather events.
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Homework Statement



The roof of a house has an area of 92.8 m^2. In a violent storm the air blows across the roof at a speed of 106.8 km/hr.

Homework Equations



Assuming that the air has a density of 1.25 kg/m^3, what pressure difference is created by the storm between the air outside and inside the house?

The Attempt at a Solution



Pressure/s = Area * density / speed (m/s)
= 92.8 * 1.25 / (106.8/3.6)
= 3.91 atm*s

how do i find the time?
or am i doing the whole thing wrong?
 
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Maybe this has something to do with the Bernoulli's principle:

\frac{\rho v^{2}}{2}+\rho g h + p = const.

But then you don't need the surface...
 

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