How Far Can a Bug Crawl on a Spinning CD Before Slipping?

AI Thread Summary
A bug crawling outward on a CD spinning at 200 RPM experiences increasing centrifugal force as it moves away from the center. The static friction force, determined by the coefficient of friction (1.2) and the bug's weight, remains constant. To find the maximum distance the bug can crawl before slipping, the centrifugal force must be equated to the frictional force. The equations used involve calculating acceleration based on the CD's rotation and applying static friction principles. The solution involves solving for the radius at which the forces balance, indicating the bug's maximum distance from the center before losing grip.
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Homework Statement


A bug crawls outward from the center of a CD spinning at 200 revolutions per min. The static friction coefficient is 1.2 between the bug and cd. How far does the bug get from the center before slipping? https://www.physicsforums.com/Nexus/editor/menupop.gif
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Homework Equations


a = ((2*pi)/T)^2*r //where T is number of seconds it takes to complete a revolution.
f <= "mu"*N // static equation.


The Attempt at a Solution


I started out by trying to find f by using "mu" * g and then trying to solve for r when i have f. So that f = "mu"*a , where a = ((2*pi)/T)^2*r. I don't know if I am even on the right track.
 
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Centrifugal force experienced by the bug when it is at a distance r fron the centre =
m(2*pi)/T)^2*r ( m = mass of the bug).[This force increases as r increases]

Friction force acting on the bug = mu*mg [This force remains constant]

Equate the above two (m gets canceled out) and solve for r. You are on the right track.
 

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