How Far Does a Pion Travel in the Lab Frame?

AI Thread Summary
The discussion revolves around calculating the distance a pion travels in the laboratory frame, given its mean lifetime and speed. The mean lifetime of the pion in the lab frame is established as 30.75 ns. Participants clarify that the distance traveled can be calculated using the formula: distance = speed x time. The correct calculation results in a distance of approximately 5.41 meters, emphasizing the importance of accuracy in time conversion and exponent handling. The thread concludes with a resolution to the initial confusion regarding the formula used.
kavamo
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Homework Statement



I have correctly figured out part a but am stuck on part b. Thanks for your help in advance.

An unstable particle called the pion has a mean lifetime of 25 ns in its own rest frame. A beam of pions travels through the laboratory at a speed of 0.587c.
(a) What is the mean lifetime of the pions as measured in the laboratory frame?
30.75 ns

(b) How far does a pion travel (as measured by laboratory observers) during this time?
m


Homework Equations



[ Delta t x c (speed of light) ] / 2

The Attempt at a Solution



using the answer from part a and converting to meters:

[(3.075E-8)(3E8)] / 2 = 4.6125 I've checked for errors and always come up with this number--which according to the web program is incorrect.

What am I not doing/understanding?
 
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kavamo said:

Homework Equations



[ Delta t x c (speed of light) ] / 2
:confused: Where in the world did you get this formula?

Hint: How fast is it moving? How long is it moving for? How do you calculate distance traveled?
 
I got the formula from my professor.
As far as I can tell it is moving at 0.587c = 176100000 m/s for 25 ns.

Distance = rate x time.

So then I suppose I would do the following:

176100000 m/s x (2.5 x 10^-10) = 0.044025 meters?
 
kavamo said:
I got the formula from my professor.
It must be meant for some specific application--but not this one.
As far as I can tell it is moving at 0.587c = 176100000 m/s for 25 ns.
Why 25 ns? Stick to the lab frame.

Distance = rate x time.
That's all you need.
 
o.k. then,

176100000m/s x (3.075 x 10^-10) = 0.05415075 ~ 0.0542 and convert to meters = 5.4 m
 
Last edited:
kavamo said:
o.k. then,

176100000m/s x (3.075 x 10^-10) = 0.05415075 ~ 0.0542 and convert to meters = 5.4 m
Two things, the first being the most important:
- check your exponents
- use a more accurate value for the time in part a (redo it); only round off at the end.
 
thank you I should have typed:

176100000m/s x (3x 10^8)x 30.75 (the answer from part a) = 5415075000

then convert from nano to meters (9 decimal spaces to the left) = 5.41 meters

which is the correct answer. Thank you for your guidance. K
 
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