How far does he run during the acceleration phase?

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A sprinter accelerates at 3.50 m/s² over a 100-meter race completed in 17 seconds. The discussion focuses on calculating the distance covered during the acceleration phase and involves setting up equations for both the acceleration and constant speed phases. Participants suggest using the equations of motion to find the time spent accelerating and the distance covered during that time. Confusion arises around plugging in values correctly for the equations. The thread emphasizes the need for clarity in setting up the motion equations to solve the problem accurately.
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If anyone could help it would be greatly appreciated! A sprinter accelerates from rest to a top speed with an acceleration whose magnitude is 3.50 m/s2. After achieving top speed, he runs the remainder of the race without speeding up or slowing down. The total race is one hundred meters long. If the total race is run in 17.00 s, how far does he run during the acceleration phase?
 
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well I'd start by setting up the equations of motion in two parts: the accelaration phase and the constant speed phase:
ie: for 0<t<t(a) s(t) = 3.5/2 * t^2 [t(a) is the time they stop accelarating]..
do the same for the constant speed (its a bit more complicated) and using your known values see what you can do
 
hey i tried doing that but cannot seem to come up with the right answer. any ideas?
 
well, when you are done accelerating what is your speed? (using t(a) as a variable) and how far have you gone? (again using t(a) and the 1st equation)
 
i don't know i keep getting confused on what to plug in where. any chance on getting help setting up the equations?
 
something like this
0<t<t(a) s(t)=3.5/2 t^2
t(a)<t<t(f) s(t) = [3.5*t(a)]*[t-t(a)] + 3.5/2*t(a)^2
 
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