How Far Should a 5.6 kg Box Be Placed for Balance?

Thread starter skandol
Start date Jun 9, 2009
Tags

Board Equilibrium Static Static equilibrium

AI Thread Summary

To balance a 1.2 kg board that is 2.0 m long and pivoted at its center, a 5.6 kg box must be placed at a calculated distance from the opposite end. The equation used for this calculation is mass1 times the distance from the pivot equals mass2 times the distance of the 5.6 kg box. The solution indicates that the 5.6 kg box should be positioned approximately 0.357 meters away from the end of the board. This ensures that the board remains in equilibrium. The calculations confirm the placement needed for balance.

Jun 9, 2009

skandol

A 1.2 kg board 2.0 m long is pivoted exactly at its center. A 2.0 kg box is at one extreme end. For the board to remain balanced, a 5.6 kg box should be placed how far away from the other end

Homework Equations

mass1(.5)(2.0)= mass2 (d)

The Attempt at a Solution

.357 meters

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Jun 9, 2009

LowlyPion

Homework Helper

Welcome to Pf.

That looks ok.

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