How far will a car travel before coming to rest?

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A car decelerates uniformly from 30 m/s to 15 m/s over a distance of 75 m. The relevant equation for this scenario is v^2 = u^2 + 2as, which can be applied to determine acceleration and the distance traveled before coming to rest. By calculating acceleration first, the final distance to rest can then be found. This method allows for a detailed understanding of the car's motion. The discussion emphasizes the importance of applying the correct physics equations to solve for distance in deceleration scenarios.
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A car is decelerating uniformly. Its velocity changes from 30m/s to 15m/s in 75m. How much further will it travel before it comes to rest?

- Please, i need a detail answer. Thanks!
 
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What equation do you think is relevant to this question?
 
v^2=u^2 + 2as, i think this equation is relevant to the question.
 
chris783 said:
v^2=u^2 + 2as, i think this equation is relevant to the question.
That's the one you need. Apply it twice: once to find the acceleration and again to find the final distance.
 
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