How far will a car travel before coming to rest?

  • Thread starter Thread starter chris783
  • Start date Start date
  • Tags Tags
    Kinematic
AI Thread Summary
A car decelerates uniformly from 30 m/s to 15 m/s over a distance of 75 m. The relevant equation for this scenario is v^2 = u^2 + 2as, which can be applied to determine acceleration and the distance traveled before coming to rest. By calculating acceleration first, the final distance to rest can then be found. This method allows for a detailed understanding of the car's motion. The discussion emphasizes the importance of applying the correct physics equations to solve for distance in deceleration scenarios.
chris783
Messages
2
Reaction score
0
A car is decelerating uniformly. Its velocity changes from 30m/s to 15m/s in 75m. How much further will it travel before it comes to rest?

- Please, i need a detail answer. Thanks!
 
Physics news on Phys.org
What equation do you think is relevant to this question?
 
v^2=u^2 + 2as, i think this equation is relevant to the question.
 
chris783 said:
v^2=u^2 + 2as, i think this equation is relevant to the question.
That's the one you need. Apply it twice: once to find the acceleration and again to find the final distance.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Friction direction change in a inclined circular bend (car on a road)
Replies
11
Views
1K
Help with question on motion: Avoiding a rear-end collision
Replies
6
Views
3K
Physic (kinematics) — Displacement of an accelerating car
Replies
7
Views
3K
Calculating Distance Traveled with Uniform Acceleration
Replies
30
Views
5K
How Far Did the Ball Roll in the First 5 Seconds?
Replies
14
Views
6K
When 2 Cars With Differing Velocities Will Meet
Replies
3
Views
4K
Questioning the Solution for Elevator vs Rock Problem
Replies
7
Views
2K
400kJ of work is exerted to reduce a car's velocity
Replies
1
Views
1K
Physics magnitude and direction?
Replies
4
Views
2K
How Far Does a Car Travel When Slowing Down?
Replies
1
Views
1K

Hot Threads

Recent Insights

Back
Top