How fast is this roller coaster?

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Homework Help Overview

The discussion revolves around a physics problem involving a roller coaster's motion through a loop-the-loop. The original poster presents a scenario where a 350 kg roller coaster starts from rest and descends a frictionless track, raising questions about its speed at a specific point and the forces acting on it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of kinetic energy and centripetal force, with attempts to derive the normal force acting on the roller coaster at point B. Questions arise regarding the relationship between the normal force and centripetal force, as well as the definitions of these forces.

Discussion Status

Participants are actively exploring the calculations related to the forces acting on the roller coaster. There is a focus on clarifying the concepts of normal force and centripetal force, with some guidance provided on how to approach the problem. Multiple interpretations of the forces involved are being considered.

Contextual Notes

Participants are working within the constraints of the problem as stated, with no additional information provided about the roller coaster's design or external factors affecting its motion.

Bottomsouth
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Homework Statement


A 350kg roller coaster starts from rest at point A and slides down the frictionless loop-the-loop shown in the accompanying figure.

http://session.masteringphysics.com/problemAsset/1027487/5/1027487.jpg
1. How fast is this roller coaster moving at point B?
2. How hard does it press against the track at point B?

Homework Equations


1. it has potential energy at A = mgh =350*9.8*25= 85750 joules
at B it has PE = 350*9.8*12=41160 joules

the difference has been changed to kinetic energy = 1/2 mv^2

1/2 mv^2 =
1/2 (350)v^2 =85750 - 41160
=16 m/s this is good.

The Attempt at a Solution



2. F = mv^2/R = 350*16^2/6 = 14933.3

It says this isn't the answer.
 
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Bottomsouth said:

The Attempt at a Solution



2. F = mv^2/R = 350*16^2/6 = 14933.3

It says this isn't the answer.

There is your problem, the centripetal force,mv2/r is the resultant force. Normal reaction acts upwards,the weight acts downwards, the resultant of these two is the centripetal force (which you can calculate and you can also calculate the weight ,mg)
 
How do I find normal force?

n-mg = C_f?

n - 350(9.81) = C_f

what is n?
 
Bottomsouth said:
How do I find normal force?

n-mg = C_f?

n - 350(9.81) = C_f

what is n?

Cf is the centripetal force mv^2/r, which you can easily find since you have v at point B, mass,m and the radius r.
 

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