How fast is this roller coaster?

AI Thread Summary
The roller coaster, starting from rest, has a potential energy of 85,750 joules at point A and 41,160 joules at point B, resulting in a speed of 16 m/s at point B. The centripetal force at point B is calculated using the formula F = mv²/r, yielding a value of 14,933.3 N, which was initially deemed incorrect. The discussion emphasizes the need to account for both the normal force and gravitational force when determining the net force acting on the roller coaster at point B. Clarification is sought on how to calculate the normal force, which is essential for solving the problem accurately.
Bottomsouth
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Homework Statement


A 350kg roller coaster starts from rest at point A and slides down the frictionless loop-the-loop shown in the accompanying figure.

http://session.masteringphysics.com/problemAsset/1027487/5/1027487.jpg
1. How fast is this roller coaster moving at point B?
2. How hard does it press against the track at point B?

Homework Equations


1. it has potential energy at A = mgh =350*9.8*25= 85750 joules
at B it has PE = 350*9.8*12=41160 joules

the difference has been changed to kinetic energy = 1/2 mv^2

1/2 mv^2 =
1/2 (350)v^2 =85750 - 41160
=16 m/s this is good.

The Attempt at a Solution



2. F = mv^2/R = 350*16^2/6 = 14933.3

It says this isn't the answer.
 
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Bottomsouth said:

The Attempt at a Solution



2. F = mv^2/R = 350*16^2/6 = 14933.3

It says this isn't the answer.

There is your problem, the centripetal force,mv2/r is the resultant force. Normal reaction acts upwards,the weight acts downwards, the resultant of these two is the centripetal force (which you can calculate and you can also calculate the weight ,mg)
 
How do I find normal force?

n-mg = C_f?

n - 350(9.81) = C_f

what is n?
 
Bottomsouth said:
How do I find normal force?

n-mg = C_f?

n - 350(9.81) = C_f

what is n?

Cf is the centripetal force mv^2/r, which you can easily find since you have v at point B, mass,m and the radius r.
 
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