How Fast Should Devita Release the Kite String?

  • Thread starter Thread starter stressedgirl
  • Start date Start date
  • Tags Tags
    Kinematics
AI Thread Summary
Devita is teaching Matthew about kite flying, with the kite at a height of 15 m and 25 m of string released, while being blown horizontally at 2.0 m/s. The discussion centers on calculating the rate at which Devita must let out the string, with initial calculations yielding an average velocity of 2.5 m/s, which contradicts the teacher's expected value of 1.6 m/s. Participants suggest sharing detailed calculations and clarifying the relationship between the kite's height, string length, and horizontal movement. The importance of accurately depicting vector components and angles in the calculations is emphasized. The conversation highlights the need for clear communication and detailed problem-solving in physics.
stressedgirl
Messages
13
Reaction score
0

Homework Statement


Devita is standing still teachnig Matthew about flying a kite. The kite is already 15 m high and she has let 25 m of string. It is now being blown directly away from her at a constant height with a horizontal velocity of 2.0 m/s. At what rate must Devita be letting out the string?

The Attempt at a Solution



Ok so first I drew vector components for the displacement. You get an angle using sin(15/25) = 36.9 deg.

Then I drew a diagram like so:
[URL]http://img819.imageshack.us/i/diagrm33.png/[/URL]

I calculated for the VAvg and got VAvg = 2.5 m/s, but my teacher says it is supposed to be 1.6. Ideas??
 
Last edited by a moderator:
Physics news on Phys.org
stressedgirl said:
Ok so first I drew vector components for the displacement. You get an angle using sin(15/25) = 36.9 deg.

Then I drew a diagram like so:
[URL]http://img819.imageshack.us/i/diagrm33.png/[/URL]

I calculated for the VAvg and got VAvg = 2.5 m/s, but my teacher says it is supposed to be 1.6. Ideas??

Sure! Plenty of ideas!

First though, your image link didn't show up in your post, possibly because it wasn't associated with some text string. http://img819.imageshack.us/i/diagrm33.png/"

Perhaps you could show the details of your calculation, and describe why it should yield the rate of string release.
 
Last edited by a moderator:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top