How great is the friction force?

AI Thread Summary
The discussion centers on calculating the friction force acting on a freezer full of ice cream when a 400-Newton horizontal force is applied. Participants emphasize the importance of using a free body diagram to visualize the forces involved, including the normal force, weight, applied force, and friction force. Since the freezer does not move, the friction force must equal the applied force of 400 N to maintain equilibrium. The consensus confirms that the friction force is indeed 400 N, as it balances the applied force. Understanding these concepts is crucial for accurately calculating friction in similar scenarios.
uwmphysics
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I was wondering if someone could help explain this. I don't understand how to calculate the friction force...

So here's the question I'm working on

You are applying a 400-Newton force to a freezer full of chocolate chip ice cream in an attempt to move it across the basement. It will not budge. The weight of the freezer (including ice cream) is 1000 N. The friction force exerted by the floor on the freezer is
a. 400 N
b. greater than 400 N but less than 1000 N
c. 1000 N
d. greater than 1000 N

thanks
 
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uwmphysics said:
I was wondering if someone could help explain this. I don't understand how to calculate the friction force...

So here's the question I'm working on

You are applying a 400-Newton force to a freezer full of chocolate chip ice cream in an attempt to move it across the basement. It will not budge. The weight of the freezer (including ice cream) is 1000 N. The friction force exerted by the floor on the freezer is
a. 400 N
b. greater than 400 N but less than 1000 N
c. 1000 N
d. greater than 1000 N

thanks

You should start with a free body diagram. What are the forces acting on the freezer? In what direction are they acting? Using the fact that the net force is zero (the acceleration is zero since the freezer is at rest), the answer should then be clear.
 
thank you...good idea. I made the diagram, and it would have an unbalenced force without friction, so i think friction has to be 400 N.

do you think I'm right?
 
Hello uwmphysics,

you are lucky, instead of calculating the movement of blocks you got a freezer full of chocolate chip ice cream :approve:

I assume the applied force is meant to point horizontally at the centre of mass of the freezer (no tilting).

In which direction does the friction force point and where is it's origin? Remember the freezer does not budge while applying 400N.

Regards,

nazzard
 
uwmphysics said:
thank you...good idea. I made the diagram, and it would have an unbalenced force without friction, so i think friction has to be 400 N.

do you think I'm right?

Ha, slow forum for me today. Your answer is correct.
 
uwmphysics said:
thank you...good idea. I made the diagram, and it would have an unbalenced force without friction, so i think friction has to be 400 N.

do you think I'm right?
Yes. Good job. (I am assuming that the person is pushing *horizontally*, otherwise the answer would be different.

The free body diagram should have 4 forces: a normal force acting upward (due to the floor pushing on the freezer), the weight of the freezer (i.e. the force of gravity, acting downward), the force applied by the person, 400 N to the right (let's say) and a static friction force to the left. Since the net force is zero, the friction force must have a magnitude equal to the force applied by the person.

It is *always* a very good idea to draw a free body diagram!

Patrick
 
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