How High Was the Basketball Dropped to Achieve a Momentum of 2.5 kgm/s?

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SUMMARY

The discussion focuses on calculating the height from which a basketball was dropped to achieve a momentum of 2.5 kgm/s. Given the mass of the basketball at 0.57 kg, the velocity can be determined using the formula for momentum (mass * velocity). The kinematic equation (vf^2) = (vi^2) + 2ah is utilized to relate velocity, acceleration, and height, confirming the correct approach to solving the problem.

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  • Understanding of momentum and its calculation (momentum = mass * velocity)
  • Familiarity with kinematic equations, specifically (vf^2) = (vi^2) + 2ah
  • Basic knowledge of gravitational acceleration (approximately 9.81 m/s²)
  • Ability to manipulate algebraic equations to solve for unknowns
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  • Learn more about kinematic equations and their applications in solving motion problems
  • Explore gravitational acceleration and its effects on falling objects
  • Practice solving problems involving momentum and height in various contexts
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TastyTyr
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Ok, I've done work on this problem, but I think that everything I try is wrong. I can't get any help from my book or my teacher because he made it up and wants up to try it. But I have no clue how to start. Please help me :cry:

A basketball (m = 0.57 kg) is dropped from rest. Just before striking the floor, the magnitude of the basketball's momentum is 2.5 kgm/s. At what height was the basketball dropped?
 
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mass * velocity = momentum right?
you know the mass so you can find velocity.
do you know any equations that include velocity, acceleration and height?
 
Oh yeah...and so I would solve for velocity first then I would use the kinematic equation,for velocity acceleration and height? (vf^2)=(vi^2)+2ah ??
 
you got it
 
Thanks a bunch!:smile:
 

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