How in the world is current passing through?

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The discussion revolves around calculating the magnetic field inside a toroidal tokamak fusion reactor with specified inner and outer radii and current specifications. The magnetic field at the inner radius is calculated to be 3.6T, raising questions about the presence of current within the torus. Participants clarify that using an Amperian loop larger than the torus would enclose zero net current, resulting in a zero magnetic field. The importance of the loop's size in relation to the toroidal structure is emphasized, as it determines the enclosed current and thus the magnetic field. Understanding the relationship between the Amperian loop and the toroidal current is crucial for accurate magnetic field calculations.
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Homework Statement



The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 900 turns of large-diameter wire, each of which carries a current of 14.0 kA.

(a) Find the magnitude of the magnetic field inside the toroid along the inner radius.
___T
(b) Find the magnitude of the magnetic field inside the toroid along the outer radius.
___T

The Attempt at a Solution



(a) I did it the way the textbook wants me to and I got 3.6T, but I don't understand, how could there be a current inside the torus? I mean if I were to enlarge my Amperian loop, I can get a current passing through

(b) Same here, if I were to draw an Amperian loop that is bigger than the torus, wouldn't it be zero? BUt the loop is still valid for it encloses the torus right?
 
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From Wikipedia:
400px-Toroidal_Inductor-Simple_with_Axes.JPG


Something like this.
 
Where is the Amperian loop in the picture?
 
Right...if you draw an amperian loop (a circle that is coaxial with the torus) that is smaller than the inner radius, you enclose no current, thus no B-field. If you draw it so the radius of the loop is between the inner and outer radii of the torus, you enclose N*I, and r*d(theta) (or your differential line element on the circumference of the amperian loop) is always parallel to the B-field (B (dot) dl = BL = B2*Pi*r. If you draw it larger than the outer radius, you enclose net 0 current, and have net 0 B-field.
 
A circle within the blue ring itself.
 
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