How intense is an earthquake of magnitude 5 compared to magnitude 3?

grant369
Messages
4
Reaction score
0
How many times more intense is the ground movement of an earthquake of magnitude 5 as compared with a magnitude of 3? Using M = log A.

Ted
 
Physics news on Phys.org
M2= 5*m1 => A2 =10^5*a1
 
huyen vyvy should not have answered this question since grant369 did not even attempt to do it himself. Fortunately, the answer huyen vyvy gives is wrong!

grant369, at least TRY! As huyen vyvy did, call the the intensity of the first earhquake A1. Your formula says log A1= 5. What is A1? Call the intensity of the second earthquake A2. You formula says log A2= 3. What is A2? A1 is how many times larger than A2?
 
oops my bad, i didn't read the question carefully enough.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top