smashbrohamme
- 97
- 1
The ball of a pinball machine is accelerated from rest to 11in/s in a distance of 4in. Determine the acceleration of the ball
V=Vo +at
A= Change of Velocity/ Change of Time
The answer is 15.1 in/s^2
The time the pinball traveled was 4inches/11in - .36sec
I can't seem to get what I am doing wrong but I am not getting 15.1in/s^2
I am doing 11in/s= 0+a(.36) A= 30.5
I also tried doing change of velocity/change of time which is just 11/.36 as well.
Since Vo= 0 The change of velocity is simply 11/in/s^2 and the change of time is simply
.36seconds
V=Vo +at
A= Change of Velocity/ Change of Time
The answer is 15.1 in/s^2
The time the pinball traveled was 4inches/11in - .36sec
I can't seem to get what I am doing wrong but I am not getting 15.1in/s^2
I am doing 11in/s= 0+a(.36) A= 30.5
I also tried doing change of velocity/change of time which is just 11/.36 as well.
Since Vo= 0 The change of velocity is simply 11/in/s^2 and the change of time is simply
.36seconds