How Is Angular Frequency Calculated for a Plank Supported by a Spring?

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SUMMARY

The angular frequency of small oscillations for a uniform plank of mass 2.0 kg and length 1.0 m, pivoted at one end and supported by a spring with a spring constant (k) of 1000 N/m, is calculated to be 39 s-1. The moment of inertia (I) for the plank is determined using the formula I = (1/3) * M * (L2), where M is the mass and L is the length. The period (T) of oscillation is derived from the equation T = 2π√(I/mgr), where r is the distance from the center of mass. The frequency (f) is then obtained by taking the inverse of the period.

PREREQUISITES
  • Understanding of angular frequency and oscillations
  • Familiarity with the moment of inertia formula for a uniform rod
  • Knowledge of spring constants and Hooke's Law
  • Basic principles of rotational dynamics
NEXT STEPS
  • Study the derivation of angular frequency in oscillatory systems
  • Learn about the moment of inertia for various shapes and its applications
  • Explore the relationship between spring constants and oscillation frequency
  • Investigate the effects of pivot points on the dynamics of oscillating bodies
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of oscillating systems and spring mechanics.

kkred
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A uniform plank of mass 2.0kg and length 1.0m is pivoted at one end
in a horizontal plane. It is supported at the other end by a spring with
k = 1000 N/m . What is the angular frequency of small oscillations? It m
may interest you to know that the moment of inertia of a uniform rod about its end is 1/3*M(L^2) where M is the mass and L is the length.


Tried to find Angular frequency by using angular momentum but I didn't find a suitable way to do it. Any suggestions?

The answer is 39s^-1
 
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use T=(2*3.14(I/mgr)^(1/2))
r is the distance from center of mass
Then inverse T to calculate the value of f.
 

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