How Is Electric Potential Energy Calculated in Electron Orbit Problems?

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The discussion revolves around calculating the electric potential energy of an electron orbiting a nucleus with a charge of +9.6E-19 C at a radius of 2.0E-10 m. The user applied the formula Ep = kQ1Q2/r and calculated the potential energy as -6.9E-18 J, while the answer key states it should be -6.9E-19 J. The user also calculated the electric potential (V) and used it to find Ep again, arriving at the same -6.9E-18 J. The discrepancy suggests a possible error in the answer key regarding the exponent. The conversation concludes with a confirmation of the user's calculations.
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Homework Statement


An electron orbits a nucleus which carries a charge of +9.6E-19 C. If the electron's orbit radius is 2.0E-10 m, what is its electric potential energy?


Homework Equations


Ep = kQ1Q2/r
V = kQ/r
V = Ep/Q


The Attempt at a Solution


I tried using Ep = kQ1Q2/r
Ep = (9E9)(9.6E-19C)(-1.6E-19C) / (2.0E-10m)
Ep = -6.9E-18 J
the answer key is saying -6.9E-19 J

and V = kQ/r , V = Ep/Q
V = (9E9)(9.6E-19C) / (2.0E-10m)
V = 43.2 V
V = Ep/Q
Ep = 43.2 V x (1.6E-19)
Ep = -6.9E-18 J
the answer key is saying -6.9E-19 J

Am I doing something wrong, or is the answer key off by an exponent?

Thanks,
 
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you seem to be very correct to me

marlon
 
ok, thank you
 
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