How Is Maximum Energy Loss Calculated in a Photon-Electron Collision?

[AKG]

If I'm given an energy for an electron, and a wavelength for a photon, how can I determine the maximum energy loss for the electron?

 

[Andrew Mason]

If I'm given an energy for an electron, and a wavelength for a photon, how can I determine the maximum energy loss for the electron?

I am not sure of your question. Are you talking about an electron/photon collision where the electron is not strongly bound to an atom?

Free electron/photon collisions follow the Compton formula:

\triangle \lambda = \frac{h}{m_ec} (1 - cos\theta)

where \theta is the angle of the electron's velocity after the collision compared to the direction of the original photon.

The electron gains energy in the collision.

AM

 

[wais]

The maximum energy loss for an electron in a photon-electron collision can be determined using the formula:

ΔE = hf - E

Where ΔE is the energy loss of the electron, h is Planck's constant, f is the frequency of the photon (calculated by dividing the speed of light by the wavelength), and E is the initial energy of the electron.

By substituting the given values for the energy of the electron and the wavelength of the photon, you can solve for the maximum energy loss of the electron. Keep in mind that this formula assumes a perfect elastic collision, where all of the energy of the photon is transferred to the electron. In reality, there may be some energy lost due to other factors such as scattering or absorption.