How is Pressure Calculated in a Moving Fluid for Sound Waves?

Click For Summary
SUMMARY

The discussion centers on the calculation of pressure in a moving fluid for sound waves, specifically referencing the wave equation for displacement waves, s = s₀ sin(kx - wt). The excess pressure at any point x and time t is derived from the change in volume, represented as δV = -Aδs = -Ak cos(kx - wt) δx. The excess pressure is then calculated using the bulk modulus equation as δP = -BδV/V. A key point of contention arises regarding the spatial consideration of fluid displacement, as the fluid at position x is actually displaced to x + s.

PREREQUISITES
  • Understanding of wave equations, specifically for sound waves.
  • Familiarity with the concept of bulk modulus in fluid mechanics.
  • Knowledge of calculus, particularly differentiation and integration as applied to wave functions.
  • Basic principles of fluid dynamics and pressure calculations.
NEXT STEPS
  • Study the derivation of the wave equation for sound waves in different media.
  • Explore the implications of the bulk modulus on pressure calculations in fluids.
  • Learn about the effects of fluid displacement on pressure in moving fluids.
  • Investigate advanced topics in fluid dynamics, such as compressible flow and shock waves.
USEFUL FOR

Students and professionals in physics, engineering, and applied mathematics, particularly those focusing on acoustics, fluid dynamics, and wave mechanics.

pardesi
Messages
337
Reaction score
0
i saw the 'proof' of the wave equation for a sound wave in a medium assuming the wave equation for a dissplacement wave.
that is the equtaion [tex]s=s_{0} \sin(kx-wt)[/tex] is supposed to hold for all points for a wave propagating in the x direction.
then using this he found out the excess pressure at any point [tex]x[/tex] a any time [tex]t[/tex].
well what he did was let at time t=0 wave started and at time t say the dislpacement of any point x be s and that of [tex]x+\delta x[/tex] be [tex]s+ \delta s[/tex].then we have
change in volume [tex]\delta V=-A\delta s=-Ak \cos(kx-wt) \delta x[/tex]
hence he said excess pressure on the material at x is [tex]\delta P=\frac{-B \delta V}{V}[/tex]
but my question is the fluid at x is no more at x but rather at x+s so how come the pressure calculated from the bulk modulus equtaion is that at x
 
Physics news on Phys.org
He is considering the region between x and ##x+\delta x##.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 49 ·
2
Replies
49
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K