How Is the Normal Force Calculated on a Charged Object on Level Ground?

AI Thread Summary
The normal force on a charged object on level ground is influenced by both gravitational and electrostatic forces. For a -2 micro-coulomb charge with a mass of 0.5 kg, the gravitational force (F_m) is calculated as 4.9 N. The electrostatic force (F_e) due to a +5 micro-coulomb charge above it is 0.7339 N, acting upward. The normal force must balance the weight of the charge and account for the upward electrostatic force, resulting in a net upward normal force. Thus, the normal force is adjusted by the presence of the upper charge, indicating a change in the overall force dynamics.
faustud.
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Homework Statement



A small charge of -2 micro-colombs which has a mass of 0.5 kg lies on level ground. A charge of +5 micro-colombs is a distance of 0.35 meters above the charge. What is the magnitude of the normal force in Newtons on the -2 micro-colomb charge? Do not ignore gravity for this problem.


Homework Equations



F_e_=k[(q1q2)/r^2] F_m_=mg

The Attempt at a Solution



F_e_=0.7339 N and F_m_=4.9N

Can anyone tell me if I'm going in the right direction with this problem?
 
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faustud. said:
F_e_=k[(q1q2)/r^2] F_m_=mg

If the upper charge had not been there, then normal reaction at point of contact on the ground would have been the weight mg. Now the upper charge is pulling at it with force F_e. How is the N changed now?
 
The N is in the positive direction, going upward?
 
The normal reaction acting on the body at the point of contact is upward.
 

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