How Is the Thickness of an Oil Film Calculated in a Plano-Convex Lens Setup?

In summary, the thickness of the oil film between the plano-convex lens and the optically flat plate can be measured and used to calculate the radii of the first and second fringes using the equation r = (2tR)^1/2.
  • #1
beethoven'smahomeboy
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A plano-convex glass lens of radius of curvature 1.8 m rests on an optically flat glass plate. Before the lens is placed on the plate a film of oil of refractive index 1.78 is deposited on the plate. The arrangement is illuminated from above with monochromatic light of 480-nm wavelength. The indexes of refraction of the lens and plate are 1.5. The radius r of a fringe is related to the thickness t of the film and the radius of curvature R of the lens through r = (2tR)^1/2. What are the radii of the first and second fringes?

How do you determine t?
 
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  • #2
The thickness of the film of oil can be determined by measuring the gap between the lens and the plate. This can be done with a caliper or other precision measuring device. Once the thickness is known, the radii of the first and second fringes can be calculated using the equation r = (2tR)^1/2, where R is the radius of curvature of the lens (1.8 m in this case). For the first fringe, r = (2*t*1.8)^1/2 and for the second fringe, r = (4*t*1.8)^1/2.
 
  • #3


To determine t, we can use the formula r = (2tR)^1/2 and solve for t. Since we know the values of r and R, we can plug them into the equation and solve for t. This will give us the thickness of the oil film, which can then be used to calculate the radii of the first and second fringes.

The first step would be to convert all the given values to the appropriate units. The radius of curvature R is given in meters, so we can leave it as is. The wavelength of light is given in nanometers, so we can convert it to meters by dividing by 10^9. The refractive index of the oil, lens, and plate are all unitless, so they do not need to be converted.

Next, we can plug in the values into the formula: r = (2tR)^1/2. We get:

r = (2t * 1.8m)^1/2

We can rearrange this equation to solve for t:

t = (r^2 / 2R)

Now, we can plug in the values for r and R:

t = ((480nm / 10^9m)^2) / (2 * 1.8m)

Simplifying this equation, we get:

t = 1.152 * 10^-13 meters

This is the thickness of the oil film. To calculate the radii of the first and second fringes, we can use the formula r = (2tR)^1/2 again, but this time we will solve for r.

For the first fringe, we can plug in the values for t and R:

r = (2 * 1.152 * 10^-13m * 1.8m)^1/2

Simplifying this equation, we get:

r = 3.27 * 10^-7 meters

For the second fringe, we can plug in the values for t and R:

r = (2 * 1.152 * 10^-13m * 1.8m * 2)^1/2

Simplifying this equation, we get:

r = 4.62 * 10^-7 meters

Therefore, the radii of the first and second fringes are 3.27 * 10^-7 meters and 4.62 * 10^-7 meters, respectively.

 

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