How Is the Throat's Cross-Sectional Area Determined Using Bernoulli's Principle?

AI Thread Summary
To determine the throat's cross-sectional area using Bernoulli's principle, the problem involves air flowing at 100 mph through a duct that narrows to a throat section, with a pressure difference of 7 inches of water measured by a U-tube. The air is treated as incompressible with a density of 0.002378 slug per cubic foot. The relevant equations include Bernoulli's equation and the equation of continuity, which relate pressure, velocity, and cross-sectional area. The final calculated area of the throat is 2.57 square feet. Understanding these principles is essential for solving similar fluid dynamics problems.
lnbanzon
Messages
1
Reaction score
0

Homework Statement



air is flowing horizontally at a speed of 100 mph through a duct 4 square feet in cross section. the duct gradually narrows down to a throat section. if a U-tube shows a difference in pressure between the throat and main sections of 7 inch of water, what is the cross sectional area of the throat? (assume that the air is incompressible and has a density of 0.002378 slug per cubic feet)

Homework Equations


The Attempt at a Solution


i already have the final answer and it is

2.57 square/feet

but i need the solution... T_T.. help

Homework Statement


Homework Equations


The Attempt at a Solution

 
Physics news on Phys.org
For a horizontal pipe what is Bernoulli's equation reduced to?

When you get that formula you can find the velocity leaving the throat section.

Do you know the equation of continuity?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top