How Is Work Calculated When Friction Is Involved?

  • Thread starter Thread starter BarCode
  • Start date Start date
  • Tags Tags
    Friction Work
AI Thread Summary
To calculate the work done by a 0.47N force pushing a 0.026kg pencil 0.26m against a friction force of 0.23N, the formula used is Work = Force x Distance. The calculated work is 0.1222J, derived from multiplying the force by the distance. Friction does not affect the work done by the applied force, as it only opposes motion rather than contributing to the work calculation. The main focus is on the applied force and the distance moved. Understanding the distinction between work done by the applied force and the opposing friction is crucial in this context.
BarCode
Messages
12
Reaction score
0

Homework Statement



Calculate the work done by a 0.47N force pushing a 0.026kg pencil 0.26m against a force of friction of 0.23N.

Knowns:

F = 0.47N
m = 0.036kg
d = 0.26m
Ff = 0.23N

Homework Equations



Work = Force x Distance

The Attempt at a Solution



Since I know work = f*d, I do
w = 0.47N * 0.26m
= 0.1222J

I'm unsure of how to add friction into the calculation.
 
Physics news on Phys.org
No. I am pretty sure you are correct. The force is 0.47N, and the distance is 0.26m. The friction is merely slowing the pencil down, which does not effect work.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

The Work of Friction: Explained in .32m
Replies
8
Views
2K
Finding the work done by a block
Replies
4
Views
3K
Why is the work done double its expected value? (conveyer belt)
2
Replies
58
Views
5K
Coefficient of Friction question for a cart going down a wooden ramp
Replies
18
Views
3K
Work and force problem with vectors
Replies
7
Views
5K
How Far Does a Box Slide Down an Inclined Plane to Compress a Spring?
Replies
16
Views
3K
Work Pulley Problem with constant speed
Replies
2
Views
975
For the friction formula when to use Fn(normal force)×mu and when F×mu
Replies
17
Views
2K
How is the minimum work needed to push a car up an inclined plane calculated?
Replies
4
Views
3K
Work done by friction on a two-block system
Replies
7
Views
3K

Hot Threads

Recent Insights

Back
Top