How long did it take for the box to travel 4.00 meters?

AI Thread Summary
A box with an initial positive velocity slides and experiences a negative acceleration of -0.25 m/s² while traveling 4.00 meters, reaching a final velocity of +0.50 m/s. The equation used to find the time, Δx = V₀t + 1/2 at², was set up correctly, but there were errors in applying the quadratic formula. The discussions highlighted confusion over the signs of acceleration and the initial velocity, which were crucial for solving the problem accurately. Participants emphasized the need to clarify the steps taken in the calculations to avoid errors. Ultimately, the correct application of the quadratic formula is essential for determining the time taken for the box to travel the specified distance.
hatcheezy
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Homework Statement


A box slides along a surface with a positive initial velocity. It the experiences an acceleration of -0.25m/s^2. After traveling 4.00 meters, its velocity is +0.50m/s. How long did it take for the boxto travel the 4.00 meters?


Homework Equations


\Deltax=Vot + 1/2 a t^2 ??


The Attempt at a Solution


4.00m=(.50m/s)t+1/2(.25m/s^2)(t^2)

(.125m/s^2)(t^2)+(.50m/s)(t)-(4.00m)

-(.50) + - \sqrt{(.50)^2-4(.125)(-4)/2(.125)}

\sqrt{2}-.50 = .9seconds?
 
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Not from my calculations.

From you problematic, v_0 is the initial velocity of the box, which is not equal to 0.5m/s

Cheers
 
You got the quadratic formula wrong. Everything is over 2a, not just 4ac.

I had to double-check your initial set-up, because you had acceleration as positive, but after a bit of algebra it's correct. I'm not sure if that was by accident or intentional. You didn't show that step, if it was intentional. V-initial isn't given, so you have to solve for V-initial in terms of V-final, a, and t, which happens to be what you got.
 
Jack21222 said:
You got the quadratic formula wrong. Everything is over 2a, not just 4ac.

I had to double-check your initial set-up, because you had acceleration as positive, but after a bit of algebra it's correct. I'm not sure if that was by accident or intentional. You didn't show that step, if it was intentional. V-initial isn't given, so you have to solve for V-initial in terms of V-final, a, and t, which happens to be what you got.

i set it over 2a...im just wondering if i set the previous equation up properly
 
hatcheezy said:
i set it over 2a...im just wondering if i set the previous equation up properly

You did, but I suspect it was due to shear luck, because you didn't show how you went from Vo to Vf, and you didn't show how you went from 'a' being negative to 'a' being positive. According to my early-morning algebra, the set-up is right, however.

And no, you didn't set it all over 2a. If you had, you would have gotten the correct answer.
 
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