How Long Does It Take a Feather to Fall 1.4 Meters on the Moon?

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To determine how long it takes for a feather to fall 1.4 meters on the Moon, the relevant physics equation is d = vi + 1/2 * a * t^2, where d is distance, vi is initial velocity, a is acceleration, and t is time. Given that the initial velocity is 0 and the acceleration due to gravity on the Moon is 1.67 m/s², the correct calculation leads to a fall time of approximately 1.29 seconds. The initial attempts to use vf = vi + at were incorrect due to misapplication. After clarification, the correct equation was identified and successfully solved. The feather's fall time on the Moon is confirmed to be 1.29 seconds.
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A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2 Determine the time for the feather to fall to the surface of the moon.

So, I wrote my given:
d=1.4 m
a= 1.67 m/s2
both initial and final velocity= 0

I know I am looking for time, but I have no idea what equation to use. I tried:
vf= vi+at , but I didn't get the right answer. The answer should be 1.29 s.
Any help would be much appreciated, please and thank you!:)
 
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Well what equation involves d,a,t and u (initial velocity)?
 
This does: d=vi+1/2*at2
but I didn't get the right answer with that either, I got .75:(
 
I got the right answer now.:)
 

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