How Long Does It Take for a Speeding Train to Pass a Stationary Observer?

  • Thread starter Thread starter Tonyt88
  • Start date Start date
  • Tags Tags
    Frames Multiple
Tonyt88
Messages
62
Reaction score
0
A train of length 15cs moves at speed 3c/5. How much time does it take to a pass a person standing on the ground? [That is, what time elapses on the person's watch between the time when he is next to the front of the train, and the time when he is next to the back of the train?] Solve this by working in the frame of the person, and then again by working in the frame of the train.
 
Physics news on Phys.org
Do you know the lorentz transformations? Time dilation and length contraction? I'm not familar with the unit cs (usually would mean a centisecond) in this context.
 
Oh, sorry.

1 cs equals (3 x 10^8 m/s)(1s) = 3 x 10^8 m

Also, I know a little bit about time dilation, though I didn't really understand my professor's lecture very well.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top