How Long Does It Take the Second Satellite to Orbit Jupiter?

AI Thread Summary
The discussion revolves around calculating the orbital period of a second satellite orbiting Jupiter, which has an orbital radius four times that of the first satellite. The first satellite completes one revolution every 16 hours. Participants emphasize the importance of showing initial problem-solving efforts before receiving assistance. Key formulas mentioned include those for centripetal acceleration and angular velocity, which are essential for determining the second satellite's orbital period. The conversation highlights the need for a solid understanding of gravitational physics to solve the problem effectively.
trainumc
Messages
4
Reaction score
0
i am comlpetely stuck on this problem

Two satellites are in circular orbits around Jupiter. One, with orbital radius r, makes one revolution every 16 h. The other satellite has orbital radius 4.0r. How long does the second satellite take to make one revolution around Jupiter?

any help please?
 
Physics news on Phys.org
trainumc said:
i am comlpetely stuck on this problem

Two satellites are in circular orbits around Jupiter. One, with orbital radius r, makes one revolution every 16 h. The other satellite has orbital radius 4.0r. How long does the second satellite take to make one revolution around Jupiter?

any help please?
Welcome to Physics Forums.

We we certainly help you, but before we do you are required to show some effort in solving the problem yourself, either by providing a attempted solution or at the very least detailing your thoughts.

The homework template is there for a reason. Please use it.
 
well i don't know how to find the height but for the acceleration i know if

G= 6.67*10^-11
M= 5.97*10^24

then V=sqrt((GM/r)

but my solutions don't seem to be working
 
You're on the right lines, but not quite there yet. I'll offer you a few hints in the right direction.

a_c = \omega^2 r

\omega = \frac{2\pi}{T}

Where T is the orbital period.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top