How Many Diffraction Orders Are Visible with a 5000 Lines/cm Grating?

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When light of wavelength 632.8 nm is incident on a 5000 lines/cm grating, the diffraction order can be calculated using the formula m(λ) = d(sinθ). The grating spacing is determined to be d = 2 x 10^-6 m, leading to a calculation of sinθ = 0.3164. The maximum diffraction order, n, is found to be 3, as sinθ cannot exceed 1. Consequently, there are three beams on either side of the central beam, totaling seven visible diffraction orders. This confirms that the maximum observable orders correspond to four distinct diffraction orders.
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1. Light of wavelength 632.8nm is normally incident upon a grating of 5000 lines/cm. How many different diffraction orders can be seen in transmission?



2. m(lambda)=d(sintheta)



3. According to my text, d=1/5000lines/cm = 2x10^-6m
and sintheta= lambda/d = 632.8x10^-9/ 2x10^6 = .3164
If I take sin^-1(.3164), I get 18 degrees.
From here, I don't know what to do because the answer is that 7 beams exist, corresponding to 4 orders, and I don't know how to get to that answer!
 
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sinθ = mλ/d.

λ/d = 0.3164. sinθ cannot be more than 1. So m should be 3. Hence there are 3 beams on either side and one central beam.
 
Thanks for your reply. Although I understand what you are saying about the 3 beams on each side with one central, how do you derive that explanation from 0.3164?
 
clockworks204 said:
Thanks for your reply. Although I understand what you are saying about the 3 beams on each side with one central, how do you derive that explanation from 0.3164?
sinθ = nλ/d. if n = 3
sinθ = 3*λ/d = 3*0.3164 = 0.9492< 1. So n cannot be more than 3.
 
Thanks, I understand now.
 
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