How Many Food Calories with Efficiency %

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SUMMARY

The discussion focuses on calculating the food calories required for an athlete to perform a specific amount of work with a given efficiency. The participant successfully determined that an out-of-condition professor metabolizes 500 kcal to perform 210,000 J of work, achieving an efficiency of 10%. For a well-conditioned athlete with an efficiency of 25%, the calculation revealed that 201 kcal are needed to perform the same work. The participant corrected their initial miscalculation by properly applying the efficiency formula and converting Joules to kilocalories accurately.

PREREQUISITES
  • Understanding of energy conversion (Joules to kilocalories)
  • Familiarity with efficiency calculations in physics
  • Knowledge of the work-energy principle
  • Basic algebra for solving equations
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  • Learn about the work-energy theorem in physics
  • Explore advanced calorimetry techniques for measuring energy expenditure
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This discussion is beneficial for students in physics or biology, fitness professionals, and anyone interested in the relationship between energy expenditure and physical performance.

Edemardil
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I figured out (a) but I am having trouble with (b):
(a) What is the efficiency of an out of condition professor who 2.10e5 J of useful work while metabolizing 500 kcal of food energy?
(b) How many food calories would a well-conditioned athlete metabolize in doing the same work with an efficiency of 25%?

Homework Equations


OE + Wnc = OEf
η = Work_out / Work_in
Work_in = η * work_out

The Attempt at a Solution


For (a) I converted the calories to Joules
1 kcal = 4184 J
500 kcal (4184J/1 kcal) = 2.1e6 J

η = W_out/W_in
η = (2.10e5J) / (2.10e6J)
η = 10%

(b) I assume I could input the 25% into the equation and work backwards but it's not giving me a correct anwser. I've tried the following:

0.25 = (2.10e5J) / (kcal)
kcal = (0.25)(2.10e5J)
kcal = 52500J
Convert the Joules to kcal and get something like 12kcal

But that's wrong also.
 
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I realize that I wrote my equation wrong at the end I said that it should be η*work_out but it is work_out/η . Here is how I finalized the problem:

η = work_out / work_in

0.25 = (2.10e5) / (kcal)

kcal = (2.10e5) / (0.25)

kcal = 840e3 J

J to kcal 1kcal = 4184 J

840e3 / 4184 = 201 kcal
 

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