How many grams of iron can be produced from 14.0g of Al and excess Fe3O4?

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To determine how many grams of iron can be produced from 14.0g of aluminum (Al) reacting with excess Fe3O4, the balanced chemical equation is 8Al + 3Fe3O4 = 9Fe + 4Al2O3. First, calculate the moles of Al in 14.0g, then use the stoichiometric ratios from the balanced equation to find the moles of iron produced. The reaction indicates that 8 moles of Al yield 9 moles of iron. Finally, convert the moles of iron to grams to obtain the final answer.
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Homework Statement


Al(s) + Fe3 O4 = Fe (s) + Al2 O3(s)
calculate how many grams of iron can be produced when 14.0g of Al are combined with excess FeO4.


Homework Equations





The Attempt at a Solution



I know that I need to balance the solution which is:
8Al(s) + 3Fe3 O4 = 9Fe (s) + 4Al2 O3(s)

net/ionic eq

8al + 3fe3o4 = 9fe + 4al2 o3

can someone please help me on this I can't get any further on finding the excess on using the net or balance ionic equation. I can't really cancel any out that are the same on both side. please help.
 
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Start with the number of MOLES of Aluminum. Find the other necessary ratios from your balanced reaction.
 
There is no net ionic reaction here (it is not happening in the solution and neither of the substances is dissociated) and the one you have is properly balanced.

Simple stoichiometry now - how many moles of Al? How many moles of iron produced per mole of Al?

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